-sin^2(x)+2cos(x)+2=0

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Solution for -sin^2(x)+2cos(x)+2=0 equation: 


Simplifying
-1sin2(x) + 2cos(x) + 2 = 0

Multiply in2s * x
-1in2sx + 2cos(x) + 2 = 0

Multiply cos * x
-1in2sx + 2cosx + 2 = 0

Reorder the terms:
2 + 2cosx + -1in2sx = 0

Solving
2 + 2cosx + -1in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 2cosx + -2 + -1in2sx = 0 + -2

Reorder the terms:
2 + -2 + 2cosx + -1in2sx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2cosx + -1in2sx = 0 + -2
2cosx + -1in2sx = 0 + -2

Combine like terms: 0 + -2 = -2
2cosx + -1in2sx = -2

Add 'in2sx' to each side of the equation.
2cosx + -1in2sx + in2sx = -2 + in2sx

Combine like terms: -1in2sx + in2sx = 0
2cosx + 0 = -2 + in2sx
2cosx = -2 + in2sx

Divide each side by '2osx'.
c = -1o-1s-1x-1 + 0.5in2o-1

Simplifying
c = -1o-1s-1x-1 + 0.5in2o-1

Reorder the terms:
c = 0.5in2o-1 + -1o-1s-1x-1

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